7(5x-5)-20=10(x+2)+25(x-3)

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Solution for 7(5x-5)-20=10(x+2)+25(x-3) equation: 



7(5x-5)-20=10(x+2)+25(x-3)

We move all terms to the left:

7(5x-5)-20-(10(x+2)+25(x-3))=0

We multiply parentheses

35x-(10(x+2)+25(x-3))-35-20=0



We calculate terms in parentheses: -(10(x+2)+25(x-3)), so:

10(x+2)+25(x-3)

We multiply parentheses

10x+25x+20-75

We add all the numbers together, and all the variables

35x-55

Back to the equation:

-(35x-55)



We add all the numbers together, and all the variables

35x-(35x-55)-55=0

We get rid of parentheses

35x-35x+55-55=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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