6(v+1)-9=4(v-1)+2

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Solution for 6(v+1)-9=4(v-1)+2 equation: 



6(v+1)-9=4(v-1)+2

We move all terms to the left:

6(v+1)-9-(4(v-1)+2)=0

We multiply parentheses

6v-(4(v-1)+2)+6-9=0



We calculate terms in parentheses: -(4(v-1)+2), so:

4(v-1)+2

We multiply parentheses

4v-4+2

We add all the numbers together, and all the variables

4v-2

Back to the equation:

-(4v-2)



We add all the numbers together, and all the variables

6v-(4v-2)-3=0

We get rid of parentheses

6v-4v+2-3=0

We add all the numbers together, and all the variables

2v-1=0

We move all terms containing v to the left, all other terms to the right

2v=1

v=1/2

v=1/2

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