7(5x-4)-8x=9(3x+2)-4(7-x)

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Solution for 7(5x-4)-8x=9(3x+2)-4(7-x) equation: 



7(5x-4)-8x=9(3x+2)-4(7-x)

We move all terms to the left:

7(5x-4)-8x-(9(3x+2)-4(7-x))=0

We add all the numbers together, and all the variables

7(5x-4)-8x-(9(3x+2)-4(-1x+7))=0

We add all the numbers together, and all the variables

-8x+7(5x-4)-(9(3x+2)-4(-1x+7))=0

We multiply parentheses

-8x+35x-(9(3x+2)-4(-1x+7))-28=0



We calculate terms in parentheses: -(9(3x+2)-4(-1x+7)), so:

9(3x+2)-4(-1x+7)

We multiply parentheses

27x+4x+18-28

We add all the numbers together, and all the variables

31x-10

Back to the equation:

-(31x-10)



We add all the numbers together, and all the variables

27x-(31x-10)-28=0

We get rid of parentheses

27x-31x+10-28=0

We add all the numbers together, and all the variables

-4x-18=0

We move all terms containing x to the left, all other terms to the right

-4x=18

x=18/-4

x=-4+1/2

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