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7x+3/7x=9000
We move all terms to the left:
7x+3/7x-(9000)=0
Domain of the equation: 7x!=0We multiply all the terms by the denominator
x!=0/7
x!=0
x∈R
7x*7x-9000*7x+3=0
Wy multiply elements
49x^2-63000x+3=0
a = 49; b = -63000; c = +3;
Δ = b2-4ac
Δ = -630002-4·49·3
Δ = 3968999412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3968999412}=\sqrt{196*20249997}=\sqrt{196}*\sqrt{20249997}=14\sqrt{20249997}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63000)-14\sqrt{20249997}}{2*49}=\frac{63000-14\sqrt{20249997}}{98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63000)+14\sqrt{20249997}}{2*49}=\frac{63000+14\sqrt{20249997}}{98} $
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