7(5d+3)=4(4d+3)

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Solution for 7(5d+3)=4(4d+3) equation:



7(5d+3)=4(4d+3)
We move all terms to the left:
7(5d+3)-(4(4d+3))=0
We multiply parentheses
35d-(4(4d+3))+21=0
We calculate terms in parentheses: -(4(4d+3)), so:
4(4d+3)
We multiply parentheses
16d+12
Back to the equation:
-(16d+12)
We get rid of parentheses
35d-16d-12+21=0
We add all the numbers together, and all the variables
19d+9=0
We move all terms containing d to the left, all other terms to the right
19d=-9
d=-9/19
d=-9/19

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