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(2x+5)(2x)=(3x)
We move all terms to the left:
(2x+5)(2x)-((3x))=0
determiningTheFunctionDomain (2x+5)2x-3x=0
We add all the numbers together, and all the variables
-3x+(2x+5)2x=0
We multiply parentheses
4x^2-3x+10x=0
We add all the numbers together, and all the variables
4x^2+7x=0
a = 4; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·4·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*4}=\frac{-14}{8} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*4}=\frac{0}{8} =0 $
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