7(5+2c)+3c=7(5+2c)+3c

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Solution for 7(5+2c)+3c=7(5+2c)+3c equation: 



7(5+2c)+3c=7(5+2c)+3c

We move all terms to the left:

7(5+2c)+3c-(7(5+2c)+3c)=0

We add all the numbers together, and all the variables

7(2c+5)+3c-(7(2c+5)+3c)=0

We add all the numbers together, and all the variables

3c+7(2c+5)-(7(2c+5)+3c)=0

We multiply parentheses

3c+14c-(7(2c+5)+3c)+35=0



We calculate terms in parentheses: -(7(2c+5)+3c), so:

7(2c+5)+3c

We add all the numbers together, and all the variables

3c+7(2c+5)

We multiply parentheses

3c+14c+35

We add all the numbers together, and all the variables

17c+35

Back to the equation:

-(17c+35)



We add all the numbers together, and all the variables

17c-(17c+35)+35=0

We get rid of parentheses

17c-17c-35+35=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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