(2x-5)+(2x)+(3x+20)=180

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Solution for (2x-5)+(2x)+(3x+20)=180 equation: 



(2x-5)+(2x)+(3x+20)=180

We move all terms to the left:

(2x-5)+(2x)+(3x+20)-(180)=0

We add all the numbers together, and all the variables

2x+(2x-5)+(3x+20)-180=0

We get rid of parentheses

2x+2x+3x-5+20-180=0

We add all the numbers together, and all the variables

7x-165=0

We move all terms containing x to the left, all other terms to the right

7x=165

x=165/7

x=23+4/7

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