7(4y+1)=-32

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Solution for 7(4y+1)=-32 equation: 



7(4y+1)=-32

We move all terms to the left:

7(4y+1)-(-32)=0

We add all the numbers together, and all the variables

7(4y+1)+32=0

We multiply parentheses

28y+7+32=0

We add all the numbers together, and all the variables

28y+39=0

We move all terms containing y to the left, all other terms to the right

28y=-39

y=-39/28

y=-1+11/28

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