1/4(12-8x)=2/3(6x)

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Solution for 1/4(12-8x)=2/3(6x) equation: 



1/4(12-8x)=2/3(6x)

We move all terms to the left:

1/4(12-8x)-(2/3(6x))=0



Domain of the equation: 4(12-8x)!=0

x∈R





Domain of the equation: 36x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/4(-8x+12)-(+2/36x)=0

We get rid of parentheses

1/4(-8x+12)-2/36x=0

We calculate fractions


36x/(-1152x^2+1728x)+(-8x(-)/(-1152x^2+1728x)=0



We calculate terms in parentheses: +(-8x(-)/(-1152x^2+1728x), so:

-8x(-)/(-1152x^2+1728x

We add all the numbers together, and all the variables

-8x0/(-1152x^2+1728x

We multiply all the terms by the denominator


-8x0

We add all the numbers together, and all the variables

-8x

Back to the equation:

+(-8x)



We get rid of parentheses

36x/(-1152x^2+1728x)-8x=0

We multiply all the terms by the denominator


-8x*(-1152x^2+1728x)+36x=0

We multiply parentheses

9216x^3-13824x^2+36x=0

We do not support expression: x^3

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