7(4x+)=6(x-2)+15

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Solution for 7(4x+)=6(x-2)+15 equation:



7(4x+)=6(x-2)+15
We move all terms to the left:
7(4x+)-(6(x-2)+15)=0
We add all the numbers together, and all the variables
7(+4x)-(6(x-2)+15)=0
We multiply parentheses
28x-(6(x-2)+15)=0
We calculate terms in parentheses: -(6(x-2)+15), so:
6(x-2)+15
We multiply parentheses
6x-12+15
We add all the numbers together, and all the variables
6x+3
Back to the equation:
-(6x+3)
We get rid of parentheses
28x-6x-3=0
We add all the numbers together, and all the variables
22x-3=0
We move all terms containing x to the left, all other terms to the right
22x=3
x=3/22
x=3/22

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