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2y-3/y=5
We move all terms to the left:
2y-3/y-(5)=0
Domain of the equation: y!=0We multiply all the terms by the denominator
y∈R
2y*y-5*y-3=0
We add all the numbers together, and all the variables
-5y+2y*y-3=0
Wy multiply elements
2y^2-5y-3=0
a = 2; b = -5; c = -3;
Δ = b2-4ac
Δ = -52-4·2·(-3)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-7}{2*2}=\frac{-2}{4} =-1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+7}{2*2}=\frac{12}{4} =3 $
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