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2(x-3)+4x=4x+2(x-4)
We move all terms to the left:
2(x-3)+4x-(4x+2(x-4))=0
We add all the numbers together, and all the variables
4x+2(x-3)-(4x+2(x-4))=0
We multiply parentheses
4x+2x-(4x+2(x-4))-6=0
We calculate terms in parentheses: -(4x+2(x-4)), so:We add all the numbers together, and all the variables
4x+2(x-4)
We multiply parentheses
4x+2x-8
We add all the numbers together, and all the variables
6x-8
Back to the equation:
-(6x-8)
6x-(6x-8)-6=0
We get rid of parentheses
6x-6x+8-6=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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