7(4j-1)=3(10j-1)

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Solution for 7(4j-1)=3(10j-1) equation: 



7(4j-1)=3(10j-1)

We move all terms to the left:

7(4j-1)-(3(10j-1))=0

We multiply parentheses

28j-(3(10j-1))-7=0



We calculate terms in parentheses: -(3(10j-1)), so:

3(10j-1)

We multiply parentheses

30j-3

Back to the equation:

-(30j-3)



We get rid of parentheses

28j-30j+3-7=0

We add all the numbers together, and all the variables

-2j-4=0

We move all terms containing j to the left, all other terms to the right

-2j=4

j=4/-2

j=-2

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