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5(3+x)=7-6(x-7)
We move all terms to the left:
5(3+x)-(7-6(x-7))=0
We add all the numbers together, and all the variables
5(x+3)-(7-6(x-7))=0
We multiply parentheses
5x-(7-6(x-7))+15=0
We calculate terms in parentheses: -(7-6(x-7)), so:We get rid of parentheses
7-6(x-7)
determiningTheFunctionDomain -6(x-7)+7
We multiply parentheses
-6x+42+7
We add all the numbers together, and all the variables
-6x+49
Back to the equation:
-(-6x+49)
5x+6x-49+15=0
We add all the numbers together, and all the variables
11x-34=0
We move all terms containing x to the left, all other terms to the right
11x=34
x=34/11
x=3+1/11
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