7(4-x)=(x-4)+5x

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Solution for 7(4-x)=(x-4)+5x equation: 



7(4-x)=(x-4)+5x

We move all terms to the left:

7(4-x)-((x-4)+5x)=0

We add all the numbers together, and all the variables

7(-1x+4)-((x-4)+5x)=0

We multiply parentheses

-7x-((x-4)+5x)+28=0



We calculate terms in parentheses: -((x-4)+5x), so:

(x-4)+5x

We add all the numbers together, and all the variables

5x+(x-4)

We get rid of parentheses

5x+x-4

We add all the numbers together, and all the variables

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

-7x-6x+4+28=0

We add all the numbers together, and all the variables

-13x+32=0

We move all terms containing x to the left, all other terms to the right

-13x=-32

x=-32/-13

x=2+6/13

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