2(2+2n)-5=-(3-n)-1

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Solution for 2(2+2n)-5=-(3-n)-1 equation: 



2(2+2n)-5=-(3-n)-1

We move all terms to the left:

2(2+2n)-5-(-(3-n)-1)=0

We add all the numbers together, and all the variables

2(2n+2)-(-(-1n+3)-1)-5=0

We multiply parentheses

4n-(-(-1n+3)-1)+4-5=0



We calculate terms in parentheses: -(-(-1n+3)-1), so:

-(-1n+3)-1

We get rid of parentheses

1n-3-1

We add all the numbers together, and all the variables

n-4

Back to the equation:

-(n-4)



We add all the numbers together, and all the variables

4n-(n-4)-1=0

We get rid of parentheses

4n-n+4-1=0

We add all the numbers together, and all the variables

3n+3=0

We move all terms containing n to the left, all other terms to the right

3n=-3

n=-3/3

n=-1

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