7(3y-6)+2(5y=3)

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Solution for 7(3y-6)+2(5y=3) equation: 



7(3y-6)+2(5y=3)

We move all terms to the left:

7(3y-6)+2(5y-(3))=0

We multiply parentheses

21y+10y-42-6=0

We add all the numbers together, and all the variables

31y-48=0

We move all terms containing y to the left, all other terms to the right

31y=48

y=48/31

y=1+17/31

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