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144=12x(x+5)
We move all terms to the left:
144-(12x(x+5))=0
We calculate terms in parentheses: -(12x(x+5)), so:We get rid of parentheses
12x(x+5)
We multiply parentheses
12x^2+60x
Back to the equation:
-(12x^2+60x)
-12x^2-60x+144=0
a = -12; b = -60; c = +144;
Δ = b2-4ac
Δ = -602-4·(-12)·144
Δ = 10512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10512}=\sqrt{144*73}=\sqrt{144}*\sqrt{73}=12\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-12\sqrt{73}}{2*-12}=\frac{60-12\sqrt{73}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+12\sqrt{73}}{2*-12}=\frac{60+12\sqrt{73}}{-24} $
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