7(3y-5)=2(10+4y)

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Solution for 7(3y-5)=2(10+4y) equation: 



7(3y-5)=2(10+4y)

We move all terms to the left:

7(3y-5)-(2(10+4y))=0

We add all the numbers together, and all the variables

7(3y-5)-(2(4y+10))=0

We multiply parentheses

21y-(2(4y+10))-35=0



We calculate terms in parentheses: -(2(4y+10)), so:

2(4y+10)

We multiply parentheses

8y+20

Back to the equation:

-(8y+20)



We get rid of parentheses

21y-8y-20-35=0

We add all the numbers together, and all the variables

13y-55=0

We move all terms containing y to the left, all other terms to the right

13y=55

y=55/13

y=4+3/13

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