8j(j+6)=0

Solution for 8j(j+6)=0 equation:

8j(j+6)=0

We multiply parentheses

8j^2+48j=0

a = 8; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·8·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*8}=\frac{-96}{16}
=-6
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*8}=\frac{0}{16}
=0
$