7(3x-x)5x=15

Solution for 7(3x-x)5x=15 equation:

7(3x-x)5x=15

We move all terms to the left:

7(3x-x)5x-(15)=0

We add all the numbers together, and all the variables

7(+2x)5x-15=0

We multiply parentheses

70x^2-15=0

a = 70; b = 0; c = -15;
Δ = b2-4ac
Δ = 02-4·70·(-15)
Δ = 4200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4200}=\sqrt{100*42}=\sqrt{100}*\sqrt{42}=10\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{42}}{2*70}=\frac{0-10\sqrt{42}}{140}
=-\frac{10\sqrt{42}}{140}
=-\frac{\sqrt{42}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{42}}{2*70}=\frac{0+10\sqrt{42}}{140}
=\frac{10\sqrt{42}}{140}
=\frac{\sqrt{42}}{14}
$