4(2-3c)=2(5c+3)

Solution for 4(2-3c)=2(5c+3) equation:

4(2-3c)=2(5c+3)

We move all terms to the left:

4(2-3c)-(2(5c+3))=0

We add all the numbers together, and all the variables

4(-3c+2)-(2(5c+3))=0

We multiply parentheses

-12c-(2(5c+3))+8=0


We calculate terms in parentheses: -(2(5c+3)), so:

2(5c+3)

We multiply parentheses

10c+6

Back to the equation:

-(10c+6)


We get rid of parentheses

-12c-10c-6+8=0

We add all the numbers together, and all the variables

-22c+2=0

We move all terms containing c to the left, all other terms to the right

-22c=-2

c=-2/-22

c=1/11