7(3x-4)=7/18

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Solution for 7(3x-4)=7/18 equation:



7(3x-4)=7/18
We move all terms to the left:
7(3x-4)-(7/18)=0
We add all the numbers together, and all the variables
7(3x-4)-(+7/18)=0
We multiply parentheses
21x-28-(+7/18)=0
We get rid of parentheses
21x-28-7/18=0
We multiply all the terms by the denominator
21x*18-7-28*18=0
We add all the numbers together, and all the variables
21x*18-511=0
Wy multiply elements
378x-511=0
We move all terms containing x to the left, all other terms to the right
378x=511
x=511/378
x=1+19/54

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