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3/5x=30x-190
We move all terms to the left:
3/5x-(30x-190)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
3/5x-30x+190=0
We multiply all the terms by the denominator
-30x*5x+190*5x+3=0
Wy multiply elements
-150x^2+950x+3=0
a = -150; b = 950; c = +3;
Δ = b2-4ac
Δ = 9502-4·(-150)·3
Δ = 904300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{904300}=\sqrt{100*9043}=\sqrt{100}*\sqrt{9043}=10\sqrt{9043}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(950)-10\sqrt{9043}}{2*-150}=\frac{-950-10\sqrt{9043}}{-300} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(950)+10\sqrt{9043}}{2*-150}=\frac{-950+10\sqrt{9043}}{-300} $
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