7(3x-2)-4(x+1)=5(2x-1)+3

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Solution for 7(3x-2)-4(x+1)=5(2x-1)+3 equation: 



7(3x-2)-4(x+1)=5(2x-1)+3

We move all terms to the left:

7(3x-2)-4(x+1)-(5(2x-1)+3)=0

We multiply parentheses

21x-4x-(5(2x-1)+3)-14-4=0



We calculate terms in parentheses: -(5(2x-1)+3), so:

5(2x-1)+3

We multiply parentheses

10x-5+3

We add all the numbers together, and all the variables

10x-2

Back to the equation:

-(10x-2)



We add all the numbers together, and all the variables

17x-(10x-2)-18=0

We get rid of parentheses

17x-10x+2-18=0

We add all the numbers together, and all the variables

7x-16=0

We move all terms containing x to the left, all other terms to the right

7x=16

x=16/7

x=2+2/7

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