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(2x+8)(x+8)=180
We move all terms to the left:
(2x+8)(x+8)-(180)=0
We multiply parentheses ..
(+2x^2+16x+8x+64)-180=0
We get rid of parentheses
2x^2+16x+8x+64-180=0
We add all the numbers together, and all the variables
2x^2+24x-116=0
a = 2; b = 24; c = -116;
Δ = b2-4ac
Δ = 242-4·2·(-116)
Δ = 1504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1504}=\sqrt{16*94}=\sqrt{16}*\sqrt{94}=4\sqrt{94}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{94}}{2*2}=\frac{-24-4\sqrt{94}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{94}}{2*2}=\frac{-24+4\sqrt{94}}{4} $
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