7(3x-1)-6(2x+3)=8(x-2)+1

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Solution for 7(3x-1)-6(2x+3)=8(x-2)+1 equation: 



7(3x-1)-6(2x+3)=8(x-2)+1

We move all terms to the left:

7(3x-1)-6(2x+3)-(8(x-2)+1)=0

We multiply parentheses

21x-12x-(8(x-2)+1)-7-18=0



We calculate terms in parentheses: -(8(x-2)+1), so:

8(x-2)+1

We multiply parentheses

8x-16+1

We add all the numbers together, and all the variables

8x-15

Back to the equation:

-(8x-15)



We add all the numbers together, and all the variables

9x-(8x-15)-25=0

We get rid of parentheses

9x-8x+15-25=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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