7(3x+12)=2(4x-10)

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Solution for 7(3x+12)=2(4x-10) equation: 



7(3x+12)=2(4x-10)

We move all terms to the left:

7(3x+12)-(2(4x-10))=0

We multiply parentheses

21x-(2(4x-10))+84=0



We calculate terms in parentheses: -(2(4x-10)), so:

2(4x-10)

We multiply parentheses

8x-20

Back to the equation:

-(8x-20)



We get rid of parentheses

21x-8x+20+84=0

We add all the numbers together, and all the variables

13x+104=0

We move all terms containing x to the left, all other terms to the right

13x=-104

x=-104/13

x=-8

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