5/7b=40

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Solution for 5/7b=40 equation: 



5/7b=40

We move all terms to the left:

5/7b-(40)=0



Domain of the equation: 7b!=0

b!=0/7

b!=0

b∈R



We multiply all the terms by the denominator


-40*7b+5=0

Wy multiply elements

-280b+5=0

We move all terms containing b to the left, all other terms to the right

-280b=-5

b=-5/-280

b=1/56

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