7(3s+1)=4(3+5)

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Solution for 7(3s+1)=4(3+5) equation:



7(3s+1)=4(3+5)
We move all terms to the left:
7(3s+1)-(4(3+5))=0
We add all the numbers together, and all the variables
7(3s+1)-(48)=0
We add all the numbers together, and all the variables
7(3s+1)-48=0
We multiply parentheses
21s+7-48=0
We add all the numbers together, and all the variables
21s-41=0
We move all terms containing s to the left, all other terms to the right
21s=41
s=41/21
s=1+20/21

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