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X2-92=-16X
We move all terms to the left:
X2-92-(-16X)=0
We add all the numbers together, and all the variables
X^2-(-16X)-92=0
We get rid of parentheses
X^2+16X-92=0
a = 1; b = 16; c = -92;
Δ = b2-4ac
Δ = 162-4·1·(-92)
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{39}}{2*1}=\frac{-16-4\sqrt{39}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{39}}{2*1}=\frac{-16+4\sqrt{39}}{2} $
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