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7(3k-2)13k=82
We move all terms to the left:
7(3k-2)13k-(82)=0
We multiply parentheses
273k^2-182k-82=0
a = 273; b = -182; c = -82;
Δ = b2-4ac
Δ = -1822-4·273·(-82)
Δ = 122668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{122668}=\sqrt{4*30667}=\sqrt{4}*\sqrt{30667}=2\sqrt{30667}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-182)-2\sqrt{30667}}{2*273}=\frac{182-2\sqrt{30667}}{546} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-182)+2\sqrt{30667}}{2*273}=\frac{182+2\sqrt{30667}}{546} $
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