-2(3x-4)+2=4(-2x+1)-2

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Solution for -2(3x-4)+2=4(-2x+1)-2 equation: 



-2(3x-4)+2=4(-2x+1)-2

We move all terms to the left:

-2(3x-4)+2-(4(-2x+1)-2)=0

We multiply parentheses

-6x-(4(-2x+1)-2)+8+2=0



We calculate terms in parentheses: -(4(-2x+1)-2), so:

4(-2x+1)-2

We multiply parentheses

-8x+4-2

We add all the numbers together, and all the variables

-8x+2

Back to the equation:

-(-8x+2)



We add all the numbers together, and all the variables

-6x-(-8x+2)+10=0

We get rid of parentheses

-6x+8x-2+10=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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