7(3-c)=7c-28

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Solution for 7(3-c)=7c-28 equation: 



7(3-c)=7c-28

We move all terms to the left:

7(3-c)-(7c-28)=0

We add all the numbers together, and all the variables

7(-1c+3)-(7c-28)=0

We multiply parentheses

-7c-(7c-28)+21=0

We get rid of parentheses

-7c-7c+28+21=0

We add all the numbers together, and all the variables

-14c+49=0

We move all terms containing c to the left, all other terms to the right

-14c=-49

c=-49/-14

c=3+1/2

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