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3(x+4)+1=2(3x+6)-9+3
We move all terms to the left:
3(x+4)+1-(2(3x+6)-9+3)=0
We multiply parentheses
3x-(2(3x+6)-9+3)+12+1=0
We calculate terms in parentheses: -(2(3x+6)-9+3), so:We add all the numbers together, and all the variables
2(3x+6)-9+3
We add all the numbers together, and all the variables
2(3x+6)-6
We multiply parentheses
6x+12-6
We add all the numbers together, and all the variables
6x+6
Back to the equation:
-(6x+6)
3x-(6x+6)+13=0
We get rid of parentheses
3x-6x-6+13=0
We add all the numbers together, and all the variables
-3x+7=0
We move all terms containing x to the left, all other terms to the right
-3x=-7
x=-7/-3
x=2+1/3
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