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7(3+5x)=3(2x-4)
We move all terms to the left:
7(3+5x)-(3(2x-4))=0
We add all the numbers together, and all the variables
7(5x+3)-(3(2x-4))=0
We multiply parentheses
35x-(3(2x-4))+21=0
We calculate terms in parentheses: -(3(2x-4)), so:We get rid of parentheses
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
35x-6x+12+21=0
We add all the numbers together, and all the variables
29x+33=0
We move all terms containing x to the left, all other terms to the right
29x=-33
x=-33/29
x=-1+4/29
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