4(n+1)=4(2-n)

Solution for 4(n+1)=4(2-n) equation:

4(n+1)=4(2-n)

We move all terms to the left:

4(n+1)-(4(2-n))=0

We add all the numbers together, and all the variables

4(n+1)-(4(-1n+2))=0

We multiply parentheses

4n-(4(-1n+2))+4=0


We calculate terms in parentheses: -(4(-1n+2)), so:

4(-1n+2)

We multiply parentheses

-4n+8

Back to the equation:

-(-4n+8)


We get rid of parentheses

4n+4n-8+4=0

We add all the numbers together, and all the variables

8n-4=0

We move all terms containing n to the left, all other terms to the right

8n=4

n=4/8

n=1/2