7(3+2x)=5(4+3x)

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Solution for 7(3+2x)=5(4+3x) equation: 



7(3+2x)=5(4+3x)

We move all terms to the left:

7(3+2x)-(5(4+3x))=0

We add all the numbers together, and all the variables

7(2x+3)-(5(3x+4))=0

We multiply parentheses

14x-(5(3x+4))+21=0



We calculate terms in parentheses: -(5(3x+4)), so:

5(3x+4)

We multiply parentheses

15x+20

Back to the equation:

-(15x+20)



We get rid of parentheses

14x-15x-20+21=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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