10((5/2)+x)=20

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Solution for 10((5/2)+x)=20 equation: 



10((5/2)+x)=20

We move all terms to the left:

10((5/2)+x)-(20)=0



Domain of the equation: 2)+x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

10((+5/2)+x)-20=0

We multiply all the terms by the denominator


10((+5-20*2)+x)=0

We add all the numbers together, and all the variables

10((-35)+x)=0

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