7(2y-5)-8=41

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Solution for 7(2y-5)-8=41 equation: 



7(2y-5)-8=41

We move all terms to the left:

7(2y-5)-8-(41)=0

We add all the numbers together, and all the variables

7(2y-5)-49=0

We multiply parentheses

14y-35-49=0

We add all the numbers together, and all the variables

14y-84=0

We move all terms containing y to the left, all other terms to the right

14y=84

y=84/14

y=6

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