7(2y+3)=7(y+10)

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Solution for 7(2y+3)=7(y+10) equation: 



7(2y+3)=7(y+10)

We move all terms to the left:

7(2y+3)-(7(y+10))=0

We multiply parentheses

14y-(7(y+10))+21=0



We calculate terms in parentheses: -(7(y+10)), so:

7(y+10)

We multiply parentheses

7y+70

Back to the equation:

-(7y+70)



We get rid of parentheses

14y-7y-70+21=0

We add all the numbers together, and all the variables

7y-49=0

We move all terms containing y to the left, all other terms to the right

7y=49

y=49/7

y=7

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