12(y-4)=7(y-4)

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Solution for 12(y-4)=7(y-4) equation: 



12(y-4)=7(y-4)

We move all terms to the left:

12(y-4)-(7(y-4))=0

We multiply parentheses

12y-(7(y-4))-48=0



We calculate terms in parentheses: -(7(y-4)), so:

7(y-4)

We multiply parentheses

7y-28

Back to the equation:

-(7y-28)



We get rid of parentheses

12y-7y+28-48=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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