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7(2x-5)-3(4x+9)=8(2x+1)-3(6x+5)
We move all terms to the left:
7(2x-5)-3(4x+9)-(8(2x+1)-3(6x+5))=0
We multiply parentheses
14x-12x-(8(2x+1)-3(6x+5))-35-27=0
We calculate terms in parentheses: -(8(2x+1)-3(6x+5)), so:We add all the numbers together, and all the variables
8(2x+1)-3(6x+5)
We multiply parentheses
16x-18x+8-15
We add all the numbers together, and all the variables
-2x-7
Back to the equation:
-(-2x-7)
2x-(-2x-7)-62=0
We get rid of parentheses
2x+2x+7-62=0
We add all the numbers together, and all the variables
4x-55=0
We move all terms containing x to the left, all other terms to the right
4x=55
x=55/4
x=13+3/4
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