(x+6)(x+2)=604(x+2)2=36

Solution for (x+6)(x+2)=604(x+2)2=36 equation:

(x+6)(x+2)=604(x+2)2=36

We move all terms to the left:

(x+6)(x+2)-(604(x+2)2)=0

We multiply parentheses ..

(+x^2+2x+6x+12)-(604(x+2)2)=0


We calculate terms in parentheses: -(604(x+2)2), so:

604(x+2)2

We multiply parentheses

1208x+2416

Back to the equation:

-(1208x+2416)


We get rid of parentheses

x^2+2x+6x-1208x+12-2416=0

We add all the numbers together, and all the variables

x^2-1200x-2404=0

a = 1; b = -1200; c = -2404;
Δ = b2-4ac
Δ = -12002-4·1·(-2404)
Δ = 1449616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1449616}=1204$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1200)-1204}{2*1}=\frac{-4}{2}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1200)+1204}{2*1}=\frac{2404}{2}
=1202
$