7(2x-4)+5+28=6(3x-4)

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Solution for 7(2x-4)+5+28=6(3x-4) equation:



7(2x-4)+5+28=6(3x-4)
We move all terms to the left:
7(2x-4)+5+28-(6(3x-4))=0
We add all the numbers together, and all the variables
7(2x-4)-(6(3x-4))+33=0
We multiply parentheses
14x-(6(3x-4))-28+33=0
We calculate terms in parentheses: -(6(3x-4)), so:
6(3x-4)
We multiply parentheses
18x-24
Back to the equation:
-(18x-24)
We add all the numbers together, and all the variables
14x-(18x-24)+5=0
We get rid of parentheses
14x-18x+24+5=0
We add all the numbers together, and all the variables
-4x+29=0
We move all terms containing x to the left, all other terms to the right
-4x=-29
x=-29/-4
x=7+1/4

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