7(a+1)-5a=5+2(4a-2)

Solution for 7(a+1)-5a=5+2(4a-2) equation:

7(a+1)-5a=5+2(4a-2)

We move all terms to the left:

7(a+1)-5a-(5+2(4a-2))=0

We add all the numbers together, and all the variables

-5a+7(a+1)-(5+2(4a-2))=0

We multiply parentheses

-5a+7a-(5+2(4a-2))+7=0


We calculate terms in parentheses: -(5+2(4a-2)), so:

5+2(4a-2)

determiningTheFunctionDomain
2(4a-2)+5

We multiply parentheses

8a-4+5

We add all the numbers together, and all the variables

8a+1

Back to the equation:

-(8a+1)


We add all the numbers together, and all the variables

2a-(8a+1)+7=0

We get rid of parentheses

2a-8a-1+7=0

We add all the numbers together, and all the variables

-6a+6=0

We move all terms containing a to the left, all other terms to the right

-6a=-6

a=-6/-6

a=1