7(2x-3)+6=2-2(-6x-20)-1

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Solution for 7(2x-3)+6=2-2(-6x-20)-1 equation: 



7(2x-3)+6=2-2(-6x-20)-1

We move all terms to the left:

7(2x-3)+6-(2-2(-6x-20)-1)=0

We multiply parentheses

14x-(2-2(-6x-20)-1)-21+6=0



We calculate terms in parentheses: -(2-2(-6x-20)-1), so:

2-2(-6x-20)-1

determiningTheFunctionDomain
-2(-6x-20)+2-1

We add all the numbers together, and all the variables

-2(-6x-20)+1

We multiply parentheses

12x+40+1

We add all the numbers together, and all the variables

12x+41

Back to the equation:

-(12x+41)



We add all the numbers together, and all the variables

14x-(12x+41)-15=0

We get rid of parentheses

14x-12x-41-15=0

We add all the numbers together, and all the variables

2x-56=0

We move all terms containing x to the left, all other terms to the right

2x=56

x=56/2

x=28

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