6x-2(x+3)=3(x+-4)+2x-2

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Solution for 6x-2(x+3)=3(x+-4)+2x-2 equation: 



6x-2(x+3)=3(x+-4)+2x-2

We move all terms to the left:

6x-2(x+3)-(3(x+-4)+2x-2)=0

We add all the numbers together, and all the variables

6x-2(x+3)-(3(x-4)+2x-2)=0

We multiply parentheses

6x-2x-(3(x-4)+2x-2)-6=0



We calculate terms in parentheses: -(3(x-4)+2x-2), so:

3(x-4)+2x-2

We add all the numbers together, and all the variables

2x+3(x-4)-2

We multiply parentheses

2x+3x-12-2

We add all the numbers together, and all the variables

5x-14

Back to the equation:

-(5x-14)



We add all the numbers together, and all the variables

4x-(5x-14)-6=0

We get rid of parentheses

4x-5x+14-6=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8

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