4(4x+3)=19x+7-3x+5

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Solution for 4(4x+3)=19x+7-3x+5 equation: 



4(4x+3)=19x+7-3x+5

We move all terms to the left:

4(4x+3)-(19x+7-3x+5)=0

We add all the numbers together, and all the variables

4(4x+3)-(16x+12)=0

We multiply parentheses

16x-(16x+12)+12=0

We get rid of parentheses

16x-16x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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